Дана геометрическая прогрессия bn Вычислите сумму 3 первых членов если b3=1/3 q=- 1/3. Created by klevskaya251017. algebra-ru

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klevskaya251017 @klevskaya251017

July 2022 1 6 Report

Дана геометрическая прогрессия bn Вычислите сумму 3 первых членов если b3=1/3 q=- 1/3

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nafanya2014

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$b_{3}=b_{2}\cdot q \Rightarrow b_{2}=\frac{b_{3}}{q}=-1\\ \\ b_{2}=b_{1}\cdot q \Rightarrow b_{1}=\frac{b_{2}}{q}=3\\ \\S_{3}=b_{1}+b_{2}+b_{3}=3+(-1)+\frac{1}{3}=2\frac{1}{3}$

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klevskaya251017 August 2022 | 0 Ответы

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klevskaya251017 July 2022 | 0 Ответы

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