37p^4q4...

July 2022 1 8 Report

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Буду очень благодарна)
a^3b^5/ab^7
-63xy^5/81xy^4
30a^2c^3/48a^3c^2
111p^6q^6/37p^4q4

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$1)\frac{a^{3}b^{5}}{ab^{7}}=\frac{a^{2}}{b^{2}}\\\\2)-\frac{63xy^{5}}{81xy^{4}}=-\frac{7y}{9}\\\\3)\frac{30a^{2}c^{3}}{48a^{3}c^{2}}=\frac{5c}{8a}\\\\4)\frac{111p^{6}q^{6}}{37p^{4}q^{4}}=3p^{2}q^{2}$

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v vethom zavete skazanoi sdvinul on s mesta dva srednih stolbana kotoryh utver2b3d7fe644ac839e9bc42f5060a9dbee 89416

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12867 July 2022 | 0 Ответы

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