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alenaviazmina
@alenaviazmina
July 2022
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Найдите скорость и ускорение точки в момент t0,если
x(t)= 3cos2t,t0= п/3
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kirichekov
Verified answer
V(t)=s'(t)
s'(t)=(3cos2t)'=3*(-sin2t)*(2t)'=-6sin2t.
v(t)=-6sin2t
t₀=π/3
v(π/3)=-6*sin(2*(π/3))=-6*sin(2π/3)=-6*(√3/2)=
-3√3 ?????
a(t)=s''(t). s''(t)=(3cos2t)''=((3cos2t)')'=(-6sin2t)'=-12cos2t
a(t)=-12cos2t
a(π/3)=-12cos(2*(π/3))=-12cosn(2π/3)=-12*(-1/2)=6
в условии что-то не верно записано. скорость <0.
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Answers & Comments
Verified answer
V(t)=s'(t)s'(t)=(3cos2t)'=3*(-sin2t)*(2t)'=-6sin2t.
v(t)=-6sin2t
t₀=π/3
v(π/3)=-6*sin(2*(π/3))=-6*sin(2π/3)=-6*(√3/2)=-3√3 ?????
a(t)=s''(t). s''(t)=(3cos2t)''=((3cos2t)')'=(-6sin2t)'=-12cos2t
a(t)=-12cos2t
a(π/3)=-12cos(2*(π/3))=-12cosn(2π/3)=-12*(-1/2)=6
в условии что-то не верно записано. скорость <0.