Ответ:
5
x
+
y
=
x+y
____
\frac{a}{4} + \frac{b}{4} = \boxed{ \frac{a + b}{4} }
4
a
b
a+b
\frac{a}{y} + \frac{2a}{y} = \frac{a + 2a}{y} = \boxed{ \frac{3a}{y} }
2a
a+2a
3a
___
\begin{gathered} \\ \frac{5 {b}^{2} }{3a} + \frac{13 {b}^{2} }{3a} = \frac{5b {}^{2} + 13b {}^{2} }{3a} = \frac{18b {}^{2} \: | \div 3}{3a \: | \div 3} = \boxed{ \frac{6b {}^{2} }{a} }\end{gathered}
5b
2
13b
+13b
3a∣÷3
18b
∣÷3
6b
\frac{x + y}{19} + \frac{2x}{19} = \frac{x + y + 2x}{19} = \boxed{ \frac{3x + y}{19} }
19
2x
x+y+2x
3x+y
\frac{2c - x}{2b} + \frac{x}{2b} = \frac{2c - x + x}{2b} = \frac{2c \: \div 2}{2b \: \div 2} = \boxed{ \frac{c}{b} }
2b
2c−x
2c−x+x
2b÷2
2c÷2
c
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Answers & Comments
Verified answer
Ответ:
5
x
+
5
y
=
5
x+y
____
\frac{a}{4} + \frac{b}{4} = \boxed{ \frac{a + b}{4} }
4
a
+
4
b
=
4
a+b
____
\frac{a}{y} + \frac{2a}{y} = \frac{a + 2a}{y} = \boxed{ \frac{3a}{y} }
y
a
+
y
2a
=
y
a+2a
=
y
3a
___
\begin{gathered} \\ \frac{5 {b}^{2} }{3a} + \frac{13 {b}^{2} }{3a} = \frac{5b {}^{2} + 13b {}^{2} }{3a} = \frac{18b {}^{2} \: | \div 3}{3a \: | \div 3} = \boxed{ \frac{6b {}^{2} }{a} }\end{gathered}
3a
5b
2
+
3a
13b
2
=
3a
5b
2
+13b
2
=
3a∣÷3
18b
2
∣÷3
=
a
6b
2
___
\frac{x + y}{19} + \frac{2x}{19} = \frac{x + y + 2x}{19} = \boxed{ \frac{3x + y}{19} }
19
x+y
+
19
2x
=
19
x+y+2x
=
19
3x+y
___
\frac{2c - x}{2b} + \frac{x}{2b} = \frac{2c - x + x}{2b} = \frac{2c \: \div 2}{2b \: \div 2} = \boxed{ \frac{c}{b} }
2b
2c−x
+
2b
x
=
2b
2c−x+x
=
2b÷2
2c÷2
=
b
c