100^1/3 * 2^8/6 * 1/5^5/3. Created by rustam3010. algebra-ru

3...

Minsk00

100^1/3 * 2^8/6 * 1/5^5/3 = (5^2*2^2)^(1/3) *2^(4/3)*5(-5/3) = 5^(2/3)*2^(2/3)*2^(4/3)*5(-5/3) =

=5^(2/3-5/3)*2^(2/3+4/3) = 5^(-3/3)*2^(6/3) =5^(-1)*2^2 =4/5 =0,8

1 votes Thanks 0

4MD

$100^{\frac{1}{3}} \cdot 2^{\frac{8}{6}} \cdot \frac{1}{5^{\frac{5}{3}}}= 5^{2 \cdot \frac{1}{3}} \cdot 2^{2 \cdot \frac{1}{3}} \cdot 2^{\frac{4}{3}} \cdot 5^{- \frac{5}{3}}} = \\ = 5^{\frac{2}{3}} \cdot 2^{\frac{2}{3}} \cdot 2^{\frac{4}{3}} \cdot 5^{- \frac{5}{3}} =5^{\frac{2}{3} - \frac{5}{3}} \cdot 2^{\frac{2}{3}+\frac{4}{3}} = 5^{-\frac{3}{3}} \cdot 2^{\frac{6}{3}} = \\ =5^{-1} \cdot 2^{2} = \frac{4}{5} =0,8$

1 votes Thanks 0

Answers & Comments

pomogite 17 pozhalujstae309489708a554f851400a87c7fab16b 85922

pomogite reshit s razyasneniem07e295464829cac3e4091a97c881aafb 8452

pomogite reshit mozhno s resheniem

pomogite vmeste s resheniem2dcc94c414123ecd986c094b68f218b9 62502

dva svetovyh lucha s dlinami voln 600 nm i 800 nm sootvetstvenno dostigayut nekoto862f22e42cb1899311019b630775535c 1834

tex to najti x v znacheniyah y

tex]...

m napryazhennost polya na rasstoyanii 6 sm budet

telo brosheno vertikalno vverh so skorostyu v0 kogda ego skorost umenshilas v

3 najti b1 i n4reshit sistemu uravnenijy 3x 1x2 2xy y2 9

рекомендуемые вопросы

Helpful Links

Helpful Social