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SchwarzerEngel
@SchwarzerEngel
September 2021
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Помогите решить x^2/2 < 2x+2/3
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DariosI
Verified answer
X²<2(2x+2/3)
x²<4x+4/3
x²-4x-4/3<0
D=16+4*4/3=16+16/3=64/3
x₁=(4-8/√3)/2=2-4/√3
x₂=(4+8/√3)/2=2+4/√3
x∈(2-4/√3; 2+4/√3)
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Answers & Comments
Verified answer
X²<2(2x+2/3)x²<4x+4/3
x²-4x-4/3<0
D=16+4*4/3=16+16/3=64/3
x₁=(4-8/√3)/2=2-4/√3
x₂=(4+8/√3)/2=2+4/√3
x∈(2-4/√3; 2+4/√3)