выполните возведение в степень: (10x²-1/3a²)³;(0,3a^5+0,5b²)³. Created by dar42. algebra-ru

3a²)³;(0,3a^5+0,5b²)³...

dar42 @dar42

July 2021 1 17 Report

выполните возведение в степень: (10x²-1/3a²)³;
(0,3a^5+0,5b²)³

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гюйс

Verified answer

$(10x^{2}-\frac{1}{3}a^{2})^{2} =100x^{4}-6\frac{2}{3} x^{2}a^{2}+\frac{1}{9}a^{4} \\ \\ (0,3a^{5}+0,5b^{2} )^{3}=0,027a^{15} +0,135a^{10}b^{2}+0,225a^{5}b^{4} +0,125b^{6}$

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