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m50704491
@m50704491
July 2022
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3a^{5} b^{5} -24a^{2}c^{6}
8a^{3}+4a^{2}b-2ab^{2}-b^{3}
25 x^{2}-10xy+y^{2}-36
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ник3709
1) 3а^5в^5-24а^2с^6=3а^2(а^3в^5-8с^6);
2) 8а^3+4а^2в-2ав^2-в^3=(8а^3-в^3)+
+(4а^2в-2ав^2)=(2а-в)(4а^2+2ав+в^2)+
+2ав(2а-в)=(2а-в)((4а^2+2ав+в^2+2ав)=
=(2а-в)(4а^2+4ав+в^2)=
=(2а-в)(2а+в)^2;
3) 25х^2-10ху+у^2-36=(5х-у)^2-36=
=(5х-у-6)(5х-у+6).
1 votes
Thanks 1
m50704491
ета всьо адельна
m50704491
ета 4 примера
ник3709
ты условие не написал, поэтому разложила на множителей
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Answers & Comments
2) 8а^3+4а^2в-2ав^2-в^3=(8а^3-в^3)+
+(4а^2в-2ав^2)=(2а-в)(4а^2+2ав+в^2)+
+2ав(2а-в)=(2а-в)((4а^2+2ав+в^2+2ав)=
=(2а-в)(4а^2+4ав+в^2)=
=(2а-в)(2а+в)^2;
3) 25х^2-10ху+у^2-36=(5х-у)^2-36=
=(5х-у-6)(5х-у+6).