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AnnaMaria12345
@AnnaMaria12345
April 2021
1
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Дан прямоугольный треугольник ADC, найдите х:
А. 1;
Б. 2;
В. 16/3 ;
Г. (4√3)/3
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Answers & Comments
Jkms1
Sin 30° = x/AB ---> 1/2 = x/AB ---> x = AB/2
tg 30° = 4/AD --> V3' = 4/AD --> AD = 4V3'/3
BC = AB
BD = AD - AB
AB^2 = BD^2 + 4^2
AB^2 = (AD - AB)^2 + 16
AB^2 = AD^2 - 2.AB.AD + AB^2 + 16
AD^2 - 2.AB.AD + 16 = 0
2.AB.AD = AD^2 + 16
2.AB.(4V3'/3) = (4V3'/3)^2 + 16
AB.(8V3'/3) = 192/9
AB = (192/9)/(8V3'/3)
AB = 8V3'/3
x = AB/2
x = (8V3'/3)/2
x = 4V3'/3
*V3' = sqrt{3}
Have a good day!!!
1 votes
Thanks 1
AnnaMaria12345
Image does not load
Jkms1
file:///storage/emulated/0/Download/20171014_151239_HDR.jpg
Jkms1
Try here.
AnnaMaria12345
Oh, well.Thank you very much)
Jkms1
Could you see?
AnnaMaria12345
No, But I don`t want hamper you.
Jkms1
Don't worry... You aren't disturbing me...
Jkms1
It's a shame we did not get it.
AnnaMaria12345
Anyway, Thank you very much
Jkms1
^^ see ya.
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Answers & Comments
tg 30° = 4/AD --> V3' = 4/AD --> AD = 4V3'/3
BC = AB
BD = AD - AB
AB^2 = BD^2 + 4^2
AB^2 = (AD - AB)^2 + 16
AB^2 = AD^2 - 2.AB.AD + AB^2 + 16
AD^2 - 2.AB.AD + 16 = 0
2.AB.AD = AD^2 + 16
2.AB.(4V3'/3) = (4V3'/3)^2 + 16
AB.(8V3'/3) = 192/9
AB = (192/9)/(8V3'/3)
AB = 8V3'/3
x = AB/2
x = (8V3'/3)/2
x = 4V3'/3
*V3' = sqrt{3}
Have a good day!!!