Найдите производную:
1) -3sin2x+5cos3x-7
2) sin(3x- 2Пи/3)
1) y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x
2) y'=cos(3x-(2pi)\3)*3 = 3cos(3x-(2pi\3))
Решение
1 y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x
2 y'=cos(3x-(2pi)\3)*3 = 3cos(3x-(2pi\3))
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Answers & Comments
1) y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x
2) y'=cos(3x-(2pi)\3)*3 = 3cos(3x-(2pi\3))
Решение
1 y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x
2 y'=cos(3x-(2pi)\3)*3 = 3cos(3x-(2pi\3))