3b^4)^2=...

July 2022 1 9 Report

Помогите пожалуйста с номером. Нужно записать в виде многочлена степени.
4)(2.4м^3 - 3/4t)^2=
6)(3/8а - 2/3b^4)^2=

Answers & Comments

tane4ka2771

$(2,4m^{3}-\frac{3}{4} t )^{2} =2,4^{2} *(m^{3}) ^{2} -2*2,4m^{3} *\frac{3}{4} t+\frac{9}{16} t^{2} =5,76m^{6} -3,6m^{3} t+\frac{9}{16}t^{2}$

$(\frac{3}{8} )^{2} *a^{2} -2*\frac{ 3}{8} a *\frac{2}{3} *b^{4} +(\frac{2}{3} )^{2}( b^{4} )^{2} =\frac{9}{64} a^{2} -\frac{1}{2} a*b^{4} +\frac{4}{9} b^{8}$

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makcim2504 Спасибо выручили. :)

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