Помогите с логарифмами!!! с подробными решениями,пожалуйста!! *В скобках число от которого находим log.
log8(8^-3)=
log3(1/27)=
lg0.0001=
log[tex] \sqrt{7} [/tex](49)=
log3/2(64/729)=
log9 x=1/2
log0.027 x=2/3
log8(8^-3)=
log3(1/27)=
lg0.0001=
log[tex] \sqrt{7} [/tex](49)=
log3/2(64/729)=
log9 x=1/2
log0.027 x=2/3
More Questions From This User See All
Answers & Comments
Verified answer
Это простоlog8 (8^(-3)) = -3
log3 (1/27) = log3 (3^(-3)) = -3
lg 0,0001 = lg (10^(-4)) = -4
log√7 (49) = log√7((√7)^4) = 4
log3/2 (64/729) = log3/2(2^6/3^6) = log3/2((2/3)^6) = -6
log9 x = 1/2; x = 9^(1/2) = √9 = 3
log0,027 x = 2/3; x = (0,0027)^(2/3) = ((0,3)^3)^(2/3) = (0,3)^2 = 0,09