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darisae
@darisae
July 2022
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3cos²x+7sinx-5=0 помогите пожалуйста!
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Verified answer
3(1 - sin²x) + 7 sinx - 5 = 0
3sin²x - 7sinx + 2 = 0
sinx = t
3t² - 7t + 2 = 0
D = 49 - 24 = 25
t = (7 + 5)/6 = 2 или t = (7 - 5)/6 = 1/3
sint = 2 sint = 1/3
нет корней t = (-1)ⁿ · arcxin(1/3) + πn
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Answers & Comments
Verified answer
3(1 - sin²x) + 7 sinx - 5 = 03sin²x - 7sinx + 2 = 0
sinx = t
3t² - 7t + 2 = 0
D = 49 - 24 = 25
t = (7 + 5)/6 = 2 или t = (7 - 5)/6 = 1/3
sint = 2 sint = 1/3
нет корней t = (-1)ⁿ · arcxin(1/3) + πn