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kolyan198
@kolyan198
October 2021
1
9
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найти значение выражения:
а) sin240°
б) cos(-210°)
в) cos 7π/6
г) cos 4π/3
д) sin 330°
е) tg 300°
ж)ctg (-225°)
з) sin (-150°)
и) tg (-225°)
к) cos 120°
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Verified answer
а) sin240° =sin(180+60)=-sin60=-√3/2
б) cos(-210°) =cos(210)=cos(180+30)=-cos30=-√3/2
в) cos 7π/6=cos(П+П/6)=-cos(П/6)=
-√3/2
г) cos 4π/3=-cos(п/3)=-1/2
д) sin 330°=sin(360-30)=-sin30=-1/2
е) tg 300° =tg(360-60)=-tg60=-√3
ж)ctg (-225°) =ctg(-225+180)=ctg(-45)=-ctg(45)=-1
з) sin (-150°)=sin(360-150)=sin210=sin(180+30)=-sin30=-1/2
и) tg (-225°)=tg(180-225)=tg(-45)=-tg45=-1
к) cos 120°
=cos(90+30)=-sin30=-1/2
49 votes
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Answers & Comments
Verified answer
а) sin240° =sin(180+60)=-sin60=-√3/2б) cos(-210°) =cos(210)=cos(180+30)=-cos30=-√3/2
в) cos 7π/6=cos(П+П/6)=-cos(П/6)=-√3/2
г) cos 4π/3=-cos(п/3)=-1/2
д) sin 330°=sin(360-30)=-sin30=-1/2
е) tg 300° =tg(360-60)=-tg60=-√3
ж)ctg (-225°) =ctg(-225+180)=ctg(-45)=-ctg(45)=-1
з) sin (-150°)=sin(360-150)=sin210=sin(180+30)=-sin30=-1/2
и) tg (-225°)=tg(180-225)=tg(-45)=-tg45=-1
к) cos 120°=cos(90+30)=-sin30=-1/2