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Qqwa
@Qqwa
July 2022
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решите НЕРАВЕНСТВО:
х^2/2 < (2х+2)/3
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nKrynka
х^2/2 < (2х+2)/3
3*(х^2) < 2*(2х+2)
3x
² -4x - 4 < 0
D = 16 + 4*3*4 = 64
x₁ = (4 - 8)/6
x₁ = - 2/3
x₂ = (4 + 8)/6
x₂ = 2
x∈ (- 2/3; 2)
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Answers & Comments
3*(х^2) < 2*(2х+2)
3x² -4x - 4 < 0
D = 16 + 4*3*4 = 64
x₁ = (4 - 8)/6
x₁ = - 2/3
x₂ = (4 + 8)/6
x₂ = 2
x∈ (- 2/3; 2)