найти 2cos(-п+β) +5sin(п/2+β), если cosβ= -1/3
2cos(-π+β)+5sin(π/2+β)=2(cosπ*cosβ+sinπ*sinβ)+5(sin(π/2)*cosβ+cos(π/2)*sinβ)=-2cosβ+5cosβ=3cosβ=3*(-⅓)=-1.
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2cos(-π+β)+5sin(π/2+β)=2(cosπ*cosβ+sinπ*sinβ)+5(sin(π/2)*cosβ+cos(π/2)*sinβ)=-2cosβ+5cosβ=3cosβ=3*(-⅓)=-1.