Найдите значение производной функции y=f(x) в точке x[tex] x_{0} [/tex], если:
f(x)=4cos2x-ctg[tex] \frac{x}{2} [/tex], [tex] x_{0} [/tex]=π/3
f(x)=4cos2x-ctg[tex] \frac{x}{2} [/tex], [tex] x_{0} [/tex]=π/3
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f(x)=4cos2x - ctg, = π/3
f`(x) = 4*2*(-sin2x) - (1/2)(-1/sin²(x/2)) = - 8sin2x + 1/[2sin²(x/2)]