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Darisha5
@Darisha5
July 2022
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Найдите область определения функции у=корень из х2-5х-14/3
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ffray
X2-5x-14>0
D=25+56=81
x1=7
x2=-2
D(y) xэ(-бескон.;-2)обединяя(7;+бескон)
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Thanks 5
ffray
включая -2 и 7
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Answers & Comments
D=25+56=81
x1=7
x2=-2
D(y) xэ(-бескон.;-2)обединяя(7;+бескон)