Решите уравнение:
1. f'(x)·g'(x)=0
f(x)=x³-3x²
g(x)=2/3√x
2. f(x)=(1+2x)(2x-1)
f'(-2)
3.φ(x)=3+x/√x
φ'(8)
4. g(x)=4sinx
g'(-π/3)
1) f'(x)*g'(x) = 0
x = 2
2)
3)
4) g(x) = 4sinx
g'(x) = 4cosx
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Answers & Comments
Verified answer
1) f'(x)*g'(x) = 0
x = 2
2)
3)
4) g(x) = 4sinx
g'(x) = 4cosx