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Barbariska911
@Barbariska911
August 2022
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найти первый отрицательный член арифметической прогрессии а1=8целых 1/2; а2=8целых 1/3
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Lesben
Verified answer
D=a2-a1, d=8 1/3 - 8 1/2 = 1/3-1/2 = -1/6, d=-1/6
an=a1+(n-1).d i eto menše čem 0
a1+(n-1).d menše čem 0
8 1/2=17/2=8,5
8,5+(n-1).(-1/6) menše čem 0
1/6.(n-1) bolše čem 8,5
n-1 bolše čem 6.8,5
n-1 bolše čem 51
n bolše čem 51+1
n bolše čem 52
Pervyj otricatelnyj člen aritmetičeskoj progresii ect a53.
a53=8,5 +(53-1).(-1/6)=8,5-52/6=8,5-26/3=25,5/3 - 26/3=-0,5/3=
=-5/30=-1/6
(a52=0)
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Answers & Comments
Verified answer
D=a2-a1, d=8 1/3 - 8 1/2 = 1/3-1/2 = -1/6, d=-1/6an=a1+(n-1).d i eto menše čem 0
a1+(n-1).d menše čem 0
8 1/2=17/2=8,5
8,5+(n-1).(-1/6) menše čem 0
1/6.(n-1) bolše čem 8,5
n-1 bolše čem 6.8,5
n-1 bolše čem 51
n bolše čem 51+1
n bolše čem 52
Pervyj otricatelnyj člen aritmetičeskoj progresii ect a53.
a53=8,5 +(53-1).(-1/6)=8,5-52/6=8,5-26/3=25,5/3 - 26/3=-0,5/3=
=-5/30=-1/6
(a52=0)