3х – 11 = 5х + 7; б) 2 (х + 1) = 2х + 2; в) –8х + 11 = 8 (3 – х).
Решение:
а) 3х – 11 = 5х + 7; б) 2 (х + 1) = 2х + 2; в) –8х + 11 = 8 (3 – х);
3х – 5х = 7 + 11; 2х + 2 = 2х + 2; –8х + 11 = 24 – 8х;
–2х = 18. 2х – 2х = 2 – 2; –8х + 8х = 24 – 11;
0 · х = 0. 0 · х = 13.
Чему равны коэффициенты a и b и сколько корней имеет уравнение?
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