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Katunya1104
@Katunya1104
July 2022
1
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Ребят, очень нужна помощь!!))
Найти точки максимума:
f(x)= 3/4 х⁴ - 2/3 х³ + 1;
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mmb1
Verified answer
f(x)= 3/4 х⁴ - 2/3 х³ + 1;
f'=3x^3-2x^2=0
x^2(3x-2)=0
x=0
x=2/3
f(0)=1
f(2/3)=3/4*16/81-2/3*8/27+1
1 votes
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Answers & Comments
Verified answer
f(x)= 3/4 х⁴ - 2/3 х³ + 1;f'=3x^3-2x^2=0
x^2(3x-2)=0
x=0
x=2/3
f(0)=1
f(2/3)=3/4*16/81-2/3*8/27+1