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elenaolenskaya
@elenaolenskaya
July 2022
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3х^2-18х+(6-х)=0 решите пожалуйста
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3х²-18х+6-х=0
3х²-19х+6=0
D=b²-4ac=19²-4×3×6=361-72=289=17²
x 1,2=(-19±17)/6
x1=(-19-17)/6=-36/6
x2=(-19+17)/6=-2/6
x1=-6
x2=-⅓
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Answers & Comments
Verified answer
3х²-18х+6-х=03х²-19х+6=0
D=b²-4ac=19²-4×3×6=361-72=289=17²
x 1,2=(-19±17)/6
x1=(-19-17)/6=-36/6
x2=(-19+17)/6=-2/6
x1=-6
x2=-⅓