решите систему уравненийх/у = 1/3х^2 + у^2 = 40. Created by vakHoma. algebra-ru

3х^2 + у^2 = 40...

01rezerv03

$\left \{ {{\frac{x}{y}=\frac{1}{3}} \atop {x^{2}+y^{2}=40}} \right.\\\\\left \{ {{y=3x} \atop {x^{2}+(3x)^{2}=40}} \right. \\\\\left \{ {{y=3x} \atop {x^{2} +9x^{2}=40 }} \right.\\\\\left \{ {{y=3x} \atop {10x^{2}=40}} \right.\\\\\left \{ {{y=3x} \atop {x^{2}=4}} \right. \\\\1)x_{1}=-2\\\\y_{1}=3*(-2)=-6\\\\2)x_{2}=2\\\\y_{2}=3*2=6\\\\Otvet:\boxed{(-2;-6),(2;6)}$

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Universalka Есть ещё одно решение

01rezerv03 Да, исправил.

Universalka

Verified answer

Ответ:

(2; 6); (-2; -6); x = 2, y = 6; x = -2, y = -6.

Объяснение:

x : y = 1 : 3,

x^2 + y^2 = 40.

y = 3x,

x^2 + (3x)^2 = 40.

y = 3x,

x^2 + 9x^2 = 40.

y = 3x,

10x^2 = 40.

y = 3x,

x^2 = 4 (40 : 10).

y = 6,

x = 2.

y = -6,

x = -2.

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Answers & Comments

Verified answer

pomogite pozhalujsta sizhu na uroke

srochno sizhu na uroke18c43e929508b81b3b1509925e92cb6a 94324

have17time for that sort of thing youre burning the candle at both ends mr

4u2 h2 60139d01704b91f34f74bb20e099e3851a 47219

4u2 h2 60

2u2 h2 75aef86286dc245b0e9462c3f17e2bdf16 72004

2u2 h2 75

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