3х^2+13x-10=0 D-? х1=?,х2=?
3х²+13х-10=0
D=169-4х3х(-10)
D=169-120
D=49 √D=7
х1=-13+7/6=-1
х2=-13-7/6=-4
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3х²+13х-10=0
D=169-4х3х(-10)
D=169-120
D=49 √D=7
х1=-13+7/6=-1
х2=-13-7/6=-4