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Mochalkapink
@Mochalkapink
July 2022
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СРОЧНО ПОМОГИТЕ ПО АЛГЕБРЕ(уровнения с квадратами): 1)х2=21 2)2х2=32 3)1/3х2=5 4)х2-0.81=0 5)(4х-9)2(в квадрате)=49
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GlebGor1998
Verified answer
1) x^2 = 21 ; x= sqrt(21)
2) 2x^2 = 32 ; x^2 = 16 ; x = + - 4
3) 1/3x^2 = 5 ; x^2 = 15 ; x= sqr(15)
4) x^2 - 0.81 =0 ; x^2 = 0.81 ; x= +- 0.9
5) (4x - 9)^2 = 49 ; (4x - 9)^2 = 7^2 ; 4x - 9 = 7 ; 4x = 7 + 9 ; 4x= 16 ; x = 4
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Answers & Comments
Verified answer
1) x^2 = 21 ; x= sqrt(21)2) 2x^2 = 32 ; x^2 = 16 ; x = + - 4
3) 1/3x^2 = 5 ; x^2 = 15 ; x= sqr(15)
4) x^2 - 0.81 =0 ; x^2 = 0.81 ; x= +- 0.9
5) (4x - 9)^2 = 49 ; (4x - 9)^2 = 7^2 ; 4x - 9 = 7 ; 4x = 7 + 9 ; 4x= 16 ; x = 4