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valyashchenko20
@valyashchenko20
July 2022
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Найти допустимые значения переменной в выражении. 2х-10
...............
0,4+1/3х
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MizoriesKun
2х-10
...............
0,4+(1/3)х
0,4+(1/3)х ≠0
(1/3) х≠ -0,4
х≠-0.4 :1/3 =-4/10 *3/1 =-12/10
х≠ -1,2
х∉(-∞;-1.2)∪(-1,2;+∞)
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MizoriesKun
обнови страничку
Edwav
Одз: 1) x≠5
Одз: 2) x≠1,2
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Answers & Comments
...............
0,4+(1/3)х
0,4+(1/3)х ≠0
(1/3) х≠ -0,4
х≠-0.4 :1/3 =-4/10 *3/1 =-12/10
х≠ -1,2
х∉(-∞;-1.2)∪(-1,2;+∞)
Одз: 2) x≠1,2