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frip
@frip
August 2022
2
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(2х+3у)^2-3х(4/3х+4у) при x=-1,038
y=√5
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Miffka18
(2x+3y)²-3x(4/3x+4y)=4x²+12xy+9y²-4-12xy=4x²+9y²-4=4*(-1,038)²+9*(√5)²-4=
=4*1,077444+9*5-4=4,309776+45-4=45,309776
Надеюсь помогла)
1 votes
Thanks 0
2000Valery2000
pltcm xnj-nj yt nfr
2000Valery2000
здесь что-то не так
2000Valery2000
там 3х*4/3х=4х^2
2000Valery2000
4х^2+12xy+9y^2-4x^2-12xy=9y^2 Y=√5 следовательно y^2=
√5*
√5 =5
9*
√5*√5=45
1 votes
Thanks 2
2000Valery2000
вот так вроде понятнее?))
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Answers & Comments
=4*1,077444+9*5-4=4,309776+45-4=45,309776
Надеюсь помогла)