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profi393000456452
@profi393000456452
August 2022
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Привет, ребят помогите решить! Математика 10 класс, тема комплексные числа. Решите 1 примерчик развернуто, а я вам за это 15 баллов.
1-3i/i-2 + 4i+1/3i-1
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sedinalana
=(1-3i)(i+2)/[(i-2)(i+2)]+(4i+1)(3i+1)/[(3i-1)(3i+1)]=
=(i+2-3i²-6i)/(i²-4) +(12i²+4i+3i+1)/(9i²-1)=(2+3-5i)/(-1-4)+(-12+1+7i)/(-9-1)=
=(5-5i)/(-5)+(-10+7i)/(-10)=-1+i+1-0,7i=0,3i
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profi393000456452
Бро, (5-5i)/(-5)+(-10( почему здесь -10, здесь должно быть -11 +7i)/(-10)
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Answers & Comments
=(i+2-3i²-6i)/(i²-4) +(12i²+4i+3i+1)/(9i²-1)=(2+3-5i)/(-1-4)+(-12+1+7i)/(-9-1)=
=(5-5i)/(-5)+(-10+7i)/(-10)=-1+i+1-0,7i=0,3i