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Stranger1111
@Stranger1111
April 2022
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Объясните пожалуйста
(log₂48)/(3+log₂6)
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uekmyfhfp
Log2 _48 = log2_(8*6) = log2_8 + log2_6 = 3 + log2_6;
log2_48 / (3+log2_6) = (3 + log2_6) / (3+ log2_6) = 1
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Answers & Comments
log2_48 / (3+log2_6) = (3 + log2_6) / (3+ log2_6) = 1