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OhYes
@OhYes
October 2021
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Четвертый член геометрической прогрессии равен 9, а ее знаменатель равен 1/3.
Найдите сумму первых шести членов этой прогрессии.
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dnepr1
Verified answer
A₄=a₁*q³ 9 = a₁*(1/3)³ a₁=9*27= 243
S₆= a₁*(q^n-1) / (q-1) = 243*((1/3)^6-1) / ((1/3)-1) =364
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Verified answer
A₄=a₁*q³ 9 = a₁*(1/3)³ a₁=9*27= 243S₆= a₁*(q^n-1) / (q-1) = 243*((1/3)^6-1) / ((1/3)-1) =364