sin(-405°)+cos750°=
cos(-780°)-tg(-225°)=
sin2,5Π+ctg(-3/4Π)=
the(-7/6Π)-ctg10/3Π=
помогите решить...#
cos(-780°)-tg(-225°)=
sin2,5Π+ctg(-3/4Π)=
the(-7/6Π)-ctg10/3Π=
помогите решить...#
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Answers & Comments
cos(720+60)-tg(-180-45)=1/2+1=3/2
sin(2p+p/2)+ctg(-p+p/4)=1+1=2
tg(-p-p/6)-ctg(3p+p/3)=-√3/3-√3/3=-2√3/3