Найдите значение выражения, если tga=2:
1) (3sina-5cosa)/(4sina+cosa);
2) (2sin^2a-sina*cosa)/(3sin^2a+2cos^2a)
1) (3sina-5cosa)/(4sina+cosa);
2) (2sin^2a-sina*cosa)/(3sin^2a+2cos^2a)
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Если tga = 2 ---> sina = 2cosa1) (3*2cosa - 5cosa)/(4*2cosa + cosa) = cosa / (9cosa) = 1/9
2) (2*(4cos²a) - 2cosa*cosa)/(3*(4cos²a)+2cos²a) = 6cos²a / (14cos²a) = 3/7