cos(3arctg(-1/3))sin(2arctg(-1)). Created by beibarus1. algebra-ru

3))sin(2arctg(-1))...

October 2021 1 13 Report

cos(3arctg(-1/3))
sin(2arctg(-1))

Answers & Comments

zarembo73 1) cos(3arctg(-1/√3))=cos(-3arctg 1/√3)=cos(3arctg 1/√3)=cos(3*π/6)=cos π/2=0.
2) sin(2arctg(-1))=sin(-2arctg 1)=-sin(2arctg 1)=-sin(2*π/4)=-sin π/2=-1.

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