August 2022 1 10 Report
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2cos(1/3x-10pi)=√3
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2cos(\frac13x-10\pi)=\sqrt3\\cos(\frac13x-10\pi)=\frac{\sqrt3}2\\\frac13x-10\pi=30^0\\\frac13x=30^0+10\pi\\x=3(30^0+10\pi)\\x=90^0+10\pi\\x\approx121.415926536^0

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