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meonsu4
@meonsu4
March 2022
2
11
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решите неравенство прошу
(x^2)+4x+4/дробь/(3^x)-27 больше или равно 0
^ - это степень
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999Dmitry999
x∈{-2}∪(3;+∞)
3 votes
Thanks 0
tlq
(x²)+4x+4/(3^x)-27≥0
x≠3
(x+2)²/3^x-27≥0
(x+2)²≥0
3^x-27>0
(x+2)²≤0
3^x-27<0
x>3
x∈(3;+∞)
х=-2
х∉(3;+∞)∪{-2}
2 votes
Thanks 0
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Answers & Comments
x∈{-2}∪(3;+∞)
x≠3
(x+2)²/3^x-27≥0
(x+2)²≥0
3^x-27>0
(x+2)²≤0
3^x-27<0
x>3
x∈(3;+∞)
х=-2
х∉(3;+∞)∪{-2}