3x-2корень x-8=0 помогите плиз
3x-2
3x2 - 2x - 8 = 0D = b2 - 4acD = 4 + 96 = 100 = 10
x1,2 = -b ± √Dx1 = 2 + 10/6= 12/6= 2x2 = 2 - 10/6 = - 8/6= - 4/3Ответ: x1 = 2 ; x2 = - 4/3
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3x-2
3x2 - 2x - 8 = 0
D = b2 - 4ac
D = 4 + 96 = 100 = 10
x1,2 = -b ± √D
x1 = 2 + 10/6= 12/6= 2
x2 = 2 - 10/6 = - 8/6= - 4/3
Ответ: x1 = 2 ; x2 = - 4/3