ПОМООГИТЕЕЕЕЕЕЕ!Решить неравенство:
1) 4x²+x-3/ 5x²-9x-2 <0
2)2+9x-5x²/ 3x²-2x-1 ≥0
1) 4x²+x-3/ 5x²-9x-2 <0
2)2+9x-5x²/ 3x²-2x-1 ≥0
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1) (4x²+x-3)/( 5x²-9x-2 )<04x²+x-3=0
D=1+48=49
x1=(-1-7)/8=-1 U x2=(-1+7)/8=0,75
5x²-9x-2=0
D=81+40=121
x1=(9-11)/10=-0,2 U x2=(9+11)/10=2
+ _ + _ +
-------------[-1]-------------(-0,2)----------[0,75]---------(2)---------------
x∈[-1;-0,2) U [0,75;2)
2)(2+9x-5x²)/ (3x²-2x-1) ≥0
5x²-9x-2=0
D=81+40=121
x1=(9-11)/10=-0,2 U x2=(9+11)/10=2
3x²-2x-1=0
D=4+12=16
x2=(2-4)/6=-1/3 U x2=(2+4)/6=1
_ + _ + _
---------------(-1/3)------------[-0,1]---------------(1)-----------------[2]-----------------
x∈(-1/3;-0,1] U (1;2]