Ответ:
f(x) = ∫ ( 1/3 x² -2x + 5) dx
f(x)= 1/3. 1/3. x³ - 2. 1/2. x² + 5x + c
f(x)= 1/9 x³ - x² + 5x + c
f(0) = 5
1/9(0)³- (0)² + 5(0) + c = 5
c= 5
f(x) = 1/9 x³ - x² + 5x + 5
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Ответ:
f(x) = ∫ ( 1/3 x² -2x + 5) dx
f(x)= 1/3. 1/3. x³ - 2. 1/2. x² + 5x + c
f(x)= 1/9 x³ - x² + 5x + c
f(0) = 5
1/9(0)³- (0)² + 5(0) + c = 5
c= 5
f(x) = 1/9 x³ - x² + 5x + 5