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AbykaRu
@AbykaRu
June 2022
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3x^2-12x+10=0 по дискриминанту
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Mimilke
3x²-12x+10=0
a=3 b=-12 c=10
D=(-12)²-4*3*10=144-120=24
x1=12-√24/2*3=12-2√6/6=2(6-√6)/6 (2 и 6 сокращаются)=6-√6/3
x2=12+√24/2*3=12+2√6/6=2(6+√6)/6=6+√6/3
Ответ:x1=6-√6/3
x2=6+√6/3
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Answers & Comments
a=3 b=-12 c=10
D=(-12)²-4*3*10=144-120=24
x1=12-√24/2*3=12-2√6/6=2(6-√6)/6 (2 и 6 сокращаются)=6-√6/3
x2=12+√24/2*3=12+2√6/6=2(6+√6)/6=6+√6/3
Ответ:x1=6-√6/3
x2=6+√6/3