Ответ:
F ' (x) = - 1/3*3x^2 + 2x + 3 = - x^2 + 2x + 3
f ' (x) > 0
- x^2 + 2x + 3 > 0
x^2 - 2x - 3 < 0
D = 1 + 3 = 4
x1 = 1 + 2 = 3;
x2 = 1 - 2 = - 1;
+ - +
---------- ( - 1) -------- ( 3) --------> x
x ∈ ( - 1; 3)
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Ответ:
F ' (x) = - 1/3*3x^2 + 2x + 3 = - x^2 + 2x + 3
f ' (x) > 0
- x^2 + 2x + 3 > 0
x^2 - 2x - 3 < 0
D = 1 + 3 = 4
x1 = 1 + 2 = 3;
x2 = 1 - 2 = - 1;
+ - +
---------- ( - 1) -------- ( 3) --------> x
x ∈ ( - 1; 3)
Подробнее - на Znanija.com - znanija.com/task/16526358#readmore
Ответ:
1...^÷&оаокпшил $/_$^&