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giyosfariza
@giyosfariza
July 2022
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f(x)=-2/3x3+8x Найдите максимум функции
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Lesben
F´(x) = -2.xˇ2+8, F´(x) =0, -2xˇ2+8=0, xˇ2=4, /x/=2
F´´(x) = -4x
F´´(2) = -8 v točke x=2 budet makcimum
F(2) = -/3.8 + 16 = 32/3Makcimum funkcii ect 32/3.
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Answers & Comments
F´´(x) = -4x
F´´(2) = -8 v točke x=2 budet makcimum
F(2) = -/3.8 + 16 = 32/3Makcimum funkcii ect 32/3.