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milerottweiler
@milerottweiler
July 2022
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Найдите сумму первых пяти членов геометрической прогрессии (xn),если а)x5=1 1/9,q=1/3;x4=121,5,q=-3.
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vsemznaika
Воспользуйся формулой x_1=-4.5
a)x₅=x₁*q₄
б)
x_1=-4.5
2 votes
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Answers & Comments
б) x_1=-4.5