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romanigga1337
@romanigga1337
August 2022
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3x^4+13x^2+13x+3=0
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katyatu72
1)3x^4-13x^2+4=0
x^2=y
3y^2-13y+4=0
D=169-48=121=11^2
y1=(13+11)/3*2=4
y2=(13-11)/3*2=1/3
x1=2
x2=-2
x3=1/sqrt3
x4=-1/sqrt3
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romanigga1337
вы 13x упустили. я пытался это так же методом подстановки решать, но тут не выходит.
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Answers & Comments
x^2=y
3y^2-13y+4=0
D=169-48=121=11^2
y1=(13+11)/3*2=4
y2=(13-11)/3*2=1/3
x1=2
x2=-2
x3=1/sqrt3
x4=-1/sqrt3