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Юлия2000р
@Юлия2000р
July 2022
1
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log3(x)+log√3(x)+log1/3(x)<6
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MizoriesKun
log_3(x)+log_√3(x)+log_(1/3)(x)<6 ОДЗ х> 0
log_3(x)+log_3¹/²(x)+log_3⁻¹
(x)<6
log_3(x)+2log_3(x) - log_3(x)<6
log_3(x)*(1+2-1)<6
2log_3(x) <6
log_3(x) < 3
х < 3³
х < 27
x∈(0;27)
1 votes
Thanks 1
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Answers & Comments
log_3(x)+log_3¹/²(x)+log_3⁻¹(x)<6
log_3(x)+2log_3(x) - log_3(x)<6
log_3(x)*(1+2-1)<6
2log_3(x) <6
log_3(x) < 3
х < 3³
х < 27
x∈(0;27)