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maxim140902
@maxim140902
October 2021
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3y^2-10y+1 > -3y^2+y-9
докажите что при любом значении y верно неравенство
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DariosI
Verified answer
3y²+3y²-10y-y+1+9>0
6y²-11y+10>0
D=121-4*6*10=121-240=-119<0 ⇒
6y²-11y+10>0 при
∀ значениях х
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Verified answer
3y²+3y²-10y-y+1+9>06y²-11y+10>0
D=121-4*6*10=121-240=-119<0 ⇒
6y²-11y+10>0 при ∀ значениях х