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dbutolina
@dbutolina
July 2022
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3(y+5)^2-3y^2 СРОЧНО
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volyad
Y(y-5)-3y(5-y)^2=0
y(y-5)-3y(y-5)^2=0
y(y-5)(1-3(y-5))=0
y(y-5)(1-3у+15)=0
у=0 или у=5 или -3у= -16: у= 16/3= 5 целых 1/3
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Answers & Comments
y(y-5)-3y(y-5)^2=0
y(y-5)(1-3(y-5))=0
y(y-5)(1-3у+15)=0
у=0 или у=5 или -3у= -16: у= 16/3= 5 целых 1/3