Ответ:
4. 3х²-4х-20=0
D=b²-4ac=(-4)²-4×3×(-20)=16+240=256 (16²)
x1,2=-b±√D/2×a=-(-4)±√256/2×3=4±16/6
x1=4+16/6=20/6=3,33
x2=4-16/6=-12/6=-2
(3,33 ; -2)
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Ответ:
4. 3х²-4х-20=0
D=b²-4ac=(-4)²-4×3×(-20)=16+240=256 (16²)
x1,2=-b±√D/2×a=-(-4)±√256/2×3=4±16/6
x1=4+16/6=20/6=3,33
x2=4-16/6=-12/6=-2
(3,33 ; -2)