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rootkryt12
@rootkryt12
August 2022
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4 - 6 задание 55б даю!!!!!!!
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IrkaShevko
Verified answer
4.
(a - 2)(a² + a + 4) = (a - 2)(a² + 2a + 4 - a) =
a³ - 8 - a(a-2) = a³ - a² + 2a - 8 = a³ - (a² - 2a + 8)
a² - 2a + 8
D = 4 - 32 < 0
=> a² - 2a + 8 > 0 ∀a
a³ - (a² - 2a + 8) < a³ ∀a
Ответ: доказано
5.
bc > 1*3 = 3
3bc > 3*3 = 9
2a + 3bc > 2*5 + 9 = 19 > 15
Ответ: доказано
6. решаем методом интервалов:
а) ____+____(8/3)_____-_____
x∈(-∞; 8/3)
б) (2x + 10 - 4 - 3x + 7)/4 ≤ 0
(-x +13)/4 ≤ 0
____+____[13]______-_______
x∈ [13; +∞)
1 votes
Thanks 2
rootkryt12
Что за перевёрнутая А?
IrkaShevko
любое
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Answers & Comments
Verified answer
4.(a - 2)(a² + a + 4) = (a - 2)(a² + 2a + 4 - a) =
a³ - 8 - a(a-2) = a³ - a² + 2a - 8 = a³ - (a² - 2a + 8)
a² - 2a + 8
D = 4 - 32 < 0
=> a² - 2a + 8 > 0 ∀a
a³ - (a² - 2a + 8) < a³ ∀a
Ответ: доказано
5.
bc > 1*3 = 3
3bc > 3*3 = 9
2a + 3bc > 2*5 + 9 = 19 > 15
Ответ: доказано
6. решаем методом интервалов:
а) ____+____(8/3)_____-_____
x∈(-∞; 8/3)
б) (2x + 10 - 4 - 3x + 7)/4 ≤ 0
(-x +13)/4 ≤ 0
____+____[13]______-_______
x∈ [13; +∞)