Ответ:

[tex]4 {x}^{2} - 4xy + {y}^{2} = \frac{9}{4} \\ {(2x - y)}^{2} = \frac{9}{4} \\ \sqrt{ {(2x - y)}^{2} } = \sqrt{ \frac{9}{4} } \\ |2x - y| = \frac{3}{2} [/tex]

Так как |a-b|=|b-a|

[tex] |y - 2x| = 1.5[/tex]